Question #58738

A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 250 mL of solution. What is the concentration of the solution?

Expert's answer

Question #58738, Chemistry / Inorganic Chemistry

A solution is prepared by dissolving 4.40 g of KSCN in enough water to make 250 mL of solution. What is the concentration of the solution?

Answer


CM=vV;v=mMr=4.497=0.045 moleCM=0.045 mole0.25L=0.18 mole/L\begin{array}{l} C_{M} = \frac{v}{V}; \\ v = \frac{m}{Mr} = \frac{4.4}{97} = 0.045 \text{ mole} \\ C_{M} = \frac{0.045 \text{ mole}}{0.25 L} = 0.18 \text{ mole}/L \\ \end{array}


The concentration of the solution is 0.18 mole/L or 0.18 M

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