Question

Calculate the ionisation energy of rubidium per atom, if light of wavelength 5.84  108 m produces electrons with a speed of 2.450x106 m/s

Answer 1

Answer on the Question #58633-Chemistry-Inorganic Chemistry

Calculate the ionisation energy of rubidium per atom, if light of wavelength 5.84 ± 10⁻⁸ m produces electrons with a speed of 2.450 ± 10⁶ ms⁻¹

$$E_{\text{light}} = E_{\text{ionisation}} + E_{\text{kinetic}}$$ $$E_{\text{ionisation}} = E_{\text{light}} - E_{\text{kinetic}}$$ $$\begin{array}{l} E_{\text{ionisation}} = \frac{hc}{\lambda} - \frac{mv^2}{2} \\ = \frac{6.626 \cdot 10^{-34} J \cdot s \times 3 \cdot 10^{8} \, \text{m}/\text{s}}{5.84 \cdot 10^{-8} \, \text{m}} - \frac{9.11 \cdot 10^{-31} \, \text{kg} \times (2.450 \cdot 10^{6} \, \text{m}/\text{s})^2}{2} \\ \approx 6.67 \cdot 10^{-19} \, J \end{array}$$

Answer: $6.67 \cdot 10^{-19} \, J$

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