Question

What is the molar mass and atomic mass of M if Cl contains 37.38mg of the compound MCl4 of 50.00mg

Answer 1

Answer on question #58455 - Chemistry - Inorganic Chemistry

Question:

What is the molar mass and atomic mass of M if Cl contains 37.38mg of the compound MCl₄ of 50.00mg.

Solution:

$$\frac{m(M)}{M(M)} \cdot \frac{m(Cl)}{M(Cl)} = 1:4$$

The mass of M in compound MCl₄:

m(M) = 50 – 37.38 = 12.62 mg

12.62/M(M) : 37.38 / 35.45 = 1:4

M(M) = 47.87 g/mol

Ar(M) = 47.87 a.m.u

Answer:

M(M) = 47.87 g/mol

Ar(M) = 47.87 a.m.u

The M is Titanium

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