A weak acid HA has Ka=10^-6. What would be the molar ratio of this acid and its salt with strong base so that the pH of the buffer solution is 5?
The formula of the pH of buffer solution:
pH = pKa(acid)+lg(C(salt)/C(acid))
5 = -Lg(10-6) + lg(C(salt)/C(acid))
5 = 6 + lg(C(salt)/C(acid))
-1 = lg(C(salt)/C(acid))
10-1 = C(salt)/C(acid)
0.1 = C(salt)/C(acid)
C(acid)/ C(salt) = 10
Answer:
The molar ratio of the acid and its salt with strong base is 10.
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