Question

how many grams of ammonia will be obtained from 40 g of nitrogen and excess of hydrogen , if the percent yield is 87% ?

Answer 1

Answer on the Question #58261 – Chemistry – Inorganic Chemistry

how many grams of ammonia will be obtained from 40 g of nitrogen and excess of hydrogen, if the percent yield is 87% ?

The reaction is:

$$N _ {2} + 3 H _ {2} = 2 N H _ {3}$$

The amount of nitrogen in moles:

$$v _ {N _ {2}} = \frac {m}{M _ {N _ {2}}} = \frac {4 0 g}{2 8 . 0 1 4 g / m o l} = 1. 4 2 9 m o l$$

Theoretical amount of ammonia produced:

$$v _ {N H _ {3}} = 2 * v _ {N _ {2}}$$

Experimental amount of ammonia produced:

$$v _ {e x p} = 0. 8 7 * v _ {N H _ {3}} = 1. 7 4 * v _ {N _ {2}}$$

Mass of produced ammonia:

$$m _ {N H _ {3}} = v _ {e x p} * M _ {N H _ {3}} = 1. 7 4 * 1. 4 2 9 m o l * 1 7. 0 3 1 g / m o l = 4 2. 3 1 3 g$$

Answer: 42.313g

http://www.AssignmentExpert.com/