Question

A sample of a substance known to contain chloride ion was dissolved in distilled water in a 1L volumetric flask. Then 25.00mL of this solution was reacted with excess silver nitrate. A precipitate of silver chloride was filtered and dried. The mass of the dry precipitate was 0.765g. What is the concentration of chloride ions?

Answer 1

Answer on Question #57247 – Chemistry – Inorganic Chemistry

Question:

A sample of a substance known to contain chloride ion was dissolved in distilled water in a 1L volumetric flask. Then 25.00mL of this solution was reacted with excess silver nitrate. A precipitate of silver chloride was filtered and dried. The mass of the dry precipitate was 0.765g. What is the concentration of chloride ions?

Answer:

A sample of a substance known to contain chloride ion was dissolved in distilled water in a 1L volumetric flask. Then 25.00mL of this solution was reacted with excess silver nitrate. A precipitate of silver chloride was filtered and dried. The mass of the dry precipitate was 0.765g. What is the concentration of chloride ions?

$$A g ^ {+} + C l ^ {-} \rightarrow A g C l \downarrow$$ $$c _ {C l ^ {-}} = \frac {n _ {A g C l}}{V} = \frac {m _ {A g C l}}{M _ {A g C l} * V} = \frac {0 . 7 6 5}{1 6 9 . 8 7 * 0 . 0 2 5} = 0. 1 8 0 m o l / L$$

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