Question #56872
how many milliliters of 3.5M NaCl must be diluted to prepare 250ml of 0.45 M NaCl
Expert's answer
N(NaCl) = 0.25 * 0.45 = 0.1125 (mol);
V(NaCl) = 0.1125 / 3.5 = 0.032 (l);
Answer: 32 ml
V(NaCl) = 0.1125 / 3.5 = 0.032 (l);
Answer: 32 ml
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