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Answer to Question #56618 in Inorganic Chemistry for Xiao min
Question #56618
40g of molten iron (II) oxide react with 10g of magnesium according to the following equation:
FeO(l)+Mg(l)--> Fe(l)+MgO(s)
(A) what is the mass of iron produced?
(B) if the actual yield of Fe is 18.8g,calculate the percentage yield of this reaction.
FeO(l)+Mg(l)--> Fe(l)+MgO(s)
(A) what is the mass of iron produced?
(B) if the actual yield of Fe is 18.8g,calculate the percentage yield of this reaction.
Expert's answer
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