Question

a solution containing 0.275 g of NaOH require 35.5ml .of HCl for neutralization. what is the normality of HCl

Answer 1

Answer on Question#56578 – Chemistry – Inorganic Chemistry

Question:

A solution containing 0.275 g of NaOH require 35.5 ml of HCl for neutralization. What is the normality of HCl?

Solution:

m(NaOH) = 0.275 g;

V(HCl) = 35.5 ml;

N(HCl) - ?

$$v = \frac{m}{M};$$

v – the number of moles NaOH (mol);

m – mass of NaOH (g);

M – molar mass of NaOH (40 g/mol);

v(NaOH) = 0.006875 mol;

NaOH + HCl → NaCl + H2O;

According to the equation: v(NaOH) : v(HCl) = 1:1;

v(NaOH) = v(HCl) = 0.006875 mol;

$$N = \frac{C}{\text{Feq}} = \frac{1}{\text{Feq}} \frac{v}{V};$$

N – the normality of the equivalent concentration (Eq/L);

v – the number of moles (mol);

C – the molar concentration (mol/L);

V – the volume of the solution (L);

According to the reaction: Feq = 1;

v(HCl) = 0.006875 mol;

V(HCl) = 0.0355 L;

N(HCl) = 0.19 Eq/L;

**Answer**: 0.19 Eq/L

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