Answer on Question #56434 – Chemistry - Inorganic Chemistry
A solution contains 0.50 M NH₃ and 1.50 M NH₄Cl. What is the maximum concentration of Mg²⁺ that can be present in such a solution (without) precipitating Mg(OH)₂?
Answer:
NH₄Cl ionizes completely. So that C(NH₄)=1.50 M.
NH₃ is a weak base. It reacts with water as:
NH₃ + H₂O = NH₄OH
NH₄OH dissociates according to:
NH₃ + H₂O = NH₄OH
1 0.5 0 0
2 -x x x
3 0.5-x x x
K_b = [NH₄⁺][OH⁻]/[NH₃]
[OH⁻] = (K_b·[NH₃])/ [NH₄⁺]
K_b(NH₄OH) = 1.85·10⁻⁵
[OH⁻] = x
[NH₄⁺] already exists in the solution from NH₄Cl. So that: C([NH₄⁺]) = 1.5+x. But x here can be ignored.
[NH₃] = 0.5-x, where x can be ignored
[OH⁻] = (1.85·10⁻⁵·0.5)/1.5 = 6.16·10⁻⁶
K_sp(Mg(OH)₂) = [Mg²⁺][OH⁻]
K_sp(Mg(OH)₂) = 5.6·10⁻¹²
[Mg²⁺] = (5.6·10⁻¹²)/(6.16·10⁻⁶) = 9.1·10⁻⁷
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