Question

Write the equilibrium dissociation reaction for acetic acid, and the expression for the equilibrium constant, Ka, which corresponds to this reaction.

Answer 1

Answer on Question #56241 - Chemistry - Inorganic Chemistry

Question:

Write the equilibrium dissociation reaction for acetic acid, and the expression for the equilibrium constant, Ka, which corresponds to this reaction.

Answer:

$$\mathrm{CH_3COOH} + \mathrm{H_2O} \leftrightarrow \mathrm{CH_3COO^-} + \mathrm{H_3O^+}$$ K = \frac{[\mathrm{CH_3COO^-}] * [\mathrm{H_3O^+}]}{[\mathrm{CH_3COOH}]

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