Question #54889 - Chemistry - Inorganic Chemistry
Question:
A student heated (4.91x10^0) grams of calcium sulfate dihydrate. How many grams of water should be lost if the sample is heated correctly?
Solution:
4.91 g m − ? C a S O 4 ‾ ⋅ 2 H 2 O → t C a S O 4 + 2 H 2 O ↑ 172 g / m o l 18 g / m o l 4.91 172 = 0.0285 m o l 2 × 0.0285 = 0.057 m o l m ( H 2 O ) = 0.057 × 18 = 1.03 g \begin{array}{c c}
4.91\,g & m - ? \\
\underline{\mathbf{CaSO_4}} \cdot 2\mathbf{H_2O} \xrightarrow{\mathbf{t}} \mathbf{CaSO_4} + 2\mathbf{H_2O} \uparrow \\
172\,g/mol & 18\,g/mol \\
\hline
\frac{4.91}{172} = 0.0285\,mol & 2 \times 0.0285 = 0.057\,mol \\
& m(\mathrm{H_2O}) = 0.057 \times 18 = 1.03\,g \\
\end{array} 4.91 g CaS O 4 ⋅ 2 H 2 O t CaS O 4 + 2 H 2 O ↑ 172 g / m o l 172 4.91 = 0.0285 m o l m − ? 18 g / m o l 2 × 0.0285 = 0.057 m o l m ( H 2 O ) = 0.057 × 18 = 1.03 g
Answer: m ( H 2 O ) = 1.03 g m(\mathrm{H_2O}) = 1.03\,g m ( H 2 O ) = 1.03 g
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