Question #53303

CaCl2 will introduce Schottky defect when added to AgCl crystal. Explain.

Expert's answer

Answer on Question #53303 – Chemistry – Inorganic Chemistry

Question:

CaCl₂ will introduce Schottky defect when CaCl₂ added to AgCl crystal. Explain.

Answer:

When mixing AgCl and CaCl₂, each added ion of Ca²⁺ replaces Ag⁺ as they have similar radii. Since the charge of Ca and Ag is of +2 and +1, respectively, it leads to the formation of positive vacancies (Schottky defect) according to the reaction:


CaCl2+2AgClCaAg0+2ClClx+VAg+\mathrm{CaCl_2} + 2\mathrm{AgCl} \rightarrow \mathrm{Ca^{0}_{Ag}} + 2\mathrm{Cl^{x}_{Cl}} + \mathrm{V^{+}_{Ag}}


It means that one mole of CaCl₂ provides one mole of Ag vacancies in crystal structure.

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