Question

2KClO sub 3, reaction arrow, 2KCl + 3O sub 2.

How many moles of O2 can be produced by letting 6.0 moles of KClO3 react based on the above equation?

Answer 1

Answer on Question #52595 - Chemistry – Inorganic Chemistry

Question

$$2 \mathrm{KClO_3} \rightarrow 2 \mathrm{KCl} + 3 \mathrm{O_2}$$

How many moles of $\mathrm{O_2}$ can be produced by letting 6.0 moles of $\mathrm{KClO_3}$ react based on the above equation?

Answer:

According to the reaction equation:

$$\begin{array}{l} 2 \text{ mol of } \mathrm{KClO_3} \text{ produce } 3 \text{ mol of } \mathrm{O_2} \\ 6.0 \text{ mol of } \mathrm{KClO_3} - x \text{ mol of } \mathrm{O_2} \\ x = \frac{6.0 \cdot 3}{2} = 9.0 \text{ mol} \end{array}$$

Answer: 9.0 mol of $\mathrm{O_2}$ can be produced

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