Question

Ethanol burns according to the following equation. If 15.0 mol of C2H5OH burns this way, how many moles of oxygen are needed?

C sub 2 H sub 5 OH + 3O sub 2, reaction arrow, 2CO sub 2 + 3H sub 2 O.

Answer 1

Answer on Question #52592 - Chemistry – Inorganic Chemistry

Question

Ethanol burns according to the following equation. If 15.0 mol of $\mathrm{C_2H_5OH}$ burns this way, how many moles of oxygen are needed?

$$\mathrm{C_2H_5OH} + 3\mathrm{O_2} \rightarrow 2\mathrm{CO_2} + 3\mathrm{H_2O}$$

Answer:

According to the reaction equation:

$$\begin{array}{l} 1 \text{ mol of } \mathrm{C_2H_5OH} \text{ needs } 3 \text{ mol of } \mathrm{O_2} \\ 15.0 \text{ mol of } \mathrm{C_2H_5OH} - x \text{ mol of } \mathrm{O_2} \\ x = \frac{15.0 \cdot 3}{1} = 45.0 \text{ mol} \end{array}$$

Answer: 45.0 mol of oxygen are needed

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