Question

How many grams of Fe are needed to combine with 4.5 moles of Cl2?

Answer 1

Answer to Question #52589, Chemistry, Inorganic Chemistry

How many grams of Fe are needed to combine with 4.5 moles of $\mathrm{Cl}_2$?

Solution:

$2\mathrm{Fe} + 3\mathrm{Cl}_2 = 2\mathrm{FeCl}_3$

$$n(Fe) = \frac{2}{3} n(Cl_2) = \frac{4.5 \times 2}{3} = 3\ \mathrm{mol}$$ $$m = n \times M_r = 3\ \mathrm{mol} \times 55.845\ \frac{\mathrm{g}}{\mathrm{mol}} = 167.535\ \mathrm{g}$$

Answer:

167.535 g

https://www.AssignmentExpert.com