Question

If 240 g of Fe is to be used in this reaction, with adequate Cl2, how many moles of FeCl3 will be produced?

Answer 1

Answer on Question #52588 - Chemistry – Inorganic Chemistry

Question

If $240\,\mathrm{g}$ of Fe is to be used in this reaction, with adequate $\mathrm{Cl}_2$, how many moles of $\mathrm{FeCl}_3$ will be produced?

Answer:

The reaction equation is:

$$2\mathrm{Fe} + 3\mathrm{Cl}_2 \rightarrow 2\mathrm{FeCl}_3$$

Number of moles of Fe is:

$$n(\mathrm{Fe}) = \frac{m}{M} = \frac{240}{55.8} = 4.3\,\mathrm{mol}$$

According to the reaction equation:

- 2 mol of Fe produce 2 mol of $\mathrm{FeCl}_3$

- 4.3 mol of $\mathrm{Fe} - x$ mol of $\mathrm{FeCl}_3$

$$x = \frac{4.3 \cdot 2}{2} = 4.3\,\mathrm{mol}$$

Answer: 4.3 mol of $\mathrm{FeCl}_3$ will be produced

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