Question

Ammonia is produced synthetically by the reaction below. How many moles of NH3 are formed when 200.0 g of N2 reacts with hydrogen?

N sub 2 + 3H sub 2, reaction arrow, 2NH sub 3.

Answer 1

Answer on Question #52444 – Chemistry – Inorganic Chemistry

Question:

Ammonia is produced synthetically by the reaction below. How many moles of $\mathrm{NH}_3$ are formed when $200.0\ \mathrm{g}$ of $\mathrm{N}_2$ reacts with hydrogen?

$$\mathrm{N}_2 + 3\mathrm{H}_2 = 2\mathrm{NH}_3$$

Answer:

First of all we have to find the amount of mol of $\mathrm{N}_2$ which was used in the reaction.

We can find number of moles in a given mass by:

$$n = \frac{\text{given mass}}{\text{Molecular Mass}}$$

So, in our case $n = \frac{200}{28} = 7.143\ \mathrm{mol}$

It is visible from the chemical reaction that from 1 mole of $\mathrm{N}_2$ we can obtain 2 mol of $\mathrm{NH}_3$, so from 7.143 mol of $\mathrm{N}_2$ we will obtain 14.286 mol of $\mathrm{NH}_3$.

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