Question #52443
If 240 g of Fe is to be used in this reaction, with adequate Cl2, how many moles of FeCl3 will be produced?
This image shows 2Fe + 3Cl sub 2, reaction arrow, 2FeCl sub 3.
This image shows 2Fe + 3Cl sub 2, reaction arrow, 2FeCl sub 3.
Expert's answer
2Fe + 3Cl2 → 2FeCI3
The calculation is based on Fe because it is limiting reactant.
The number of moles of Fe is 240g/56g/mole=4.3moles
The molar ratio of Fe/FeCI3=1:1
So, the number of moles of FeCI3 is 4.3 moles.
The calculation is based on Fe because it is limiting reactant.
The number of moles of Fe is 240g/56g/mole=4.3moles
The molar ratio of Fe/FeCI3=1:1
So, the number of moles of FeCI3 is 4.3 moles.
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