Question #52440

Ethanol burns according to the following equation. If 15.0 mol of C2H5OH burns this way, how many moles of oxygen are needed?

Expert's answer

Answer on Question #52440 - Chemistry – Inorganic Chemistry

Question

Ethanol burns according to the following equation. If 15.0 mol of C2H5OH\mathrm{C_2H_5OH} burns this way, how many moles of oxygen are needed?

Answer:

According to the reaction equation:


1 mol of C2H5OH needs 3 mol of O215.0 mol of C2H5OHx mol of O2x=15.031=45.0 mol\begin{array}{l} 1 \text{ mol of } \mathrm{C_2H_5OH} \text{ needs } 3 \text{ mol of } \mathrm{O_2} \\ 15.0 \text{ mol of } \mathrm{C_2H_5OH} - x \text{ mol of } \mathrm{O_2} \\ x = \frac{15.0 \cdot 3}{1} = 45.0 \text{ mol} \end{array}

Answer: 45.0 mol of oxygen

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