Question

7.004x10^26 molecules of CHCl3

Answer 1

Answer on Question #49899 – Chemistry - Inorganic Chemistry

7.004×10²⁶ molecules of CHCl₃

Solution:

$$\begin{array}{l} v = \frac{m}{M_{r}} \\ v = \frac{N}{N_{a}} \\ \end{array}$$ $$M_{r}(CHCl_{3}) = 119.38 \text{ g/mol}$$ $$N_{a} = 6.022 \times 10^{23} \text{ mol}^{-1}$$ $$m = \frac{N \times M_{r}}{N_{a}} = \frac{7.004 \times 10^{26} \times 119.38}{6.022 \times 10^{23}} = 1.38 \times 10^{5} \text{ g} = 138 \text{ kg}$$

Annswer:

138 kg

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