Question

A sample of gas is heated from -15.0 0C to 28.5 0C. What was its original

volume if the volume at 18.5 0C is 2.65 liters?

Answer 1

Question #49833, Chemistry, Inorganic Chemistry

A sample of gas is heated from -15.0 0C to 28.5 0C. What was its original volume if the volume at 18.5 0C is 2.65 liters?

Answer:

T1=-15+273 K

T2=18.5 +273 K

$$\begin{array}{l} pV = nRT \\ \frac{V}{T} \frac{nR}{p} \\ \frac{V1}{T1} \frac{V2}{T2} \\ V1 = \frac{T1V2}{T2} \\ V1 = \frac{(-15 + 273)2.65}{18.5 + 273} = 2.345 \, \text{L} \end{array}$$

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