Question #49691

What's the sodium hydroxide solution is standardized using 0.502 g of solid acid H2C2O4. Find the molarity of the base if 30.50 mL are required for the titration to a phenolphthalein endpoint?

Expert's answer

Answer to Question #49691, Chemistry, Inorganic Chemistry

What's the sodium hydroxide solution is standardized using 0.502 g of solid acid H₂C₂O₄. Find the molarity of the base if 30.50 mL are required for the titration to a phenolphthalein endpoint?

Solution:


H2C2O4+2NaOHNa2C2O4+2H2O\mathrm{H_2C_2O_4} + 2\mathrm{NaOH} \rightarrow \mathrm{Na_2C_2O_4} + 2\mathrm{H_2O}c=nVc = \frac{n}{V}n(NaOH)=2×n(H2C2O4)=2×m(H2C2O4)Mr(H2C2O4)n(\mathrm{NaOH}) = 2 \times n(\mathrm{H_2C_2O_4}) = \frac{2 \times m(\mathrm{H_2C_2O_4})}{M_r(\mathrm{H_2C_2O_4})}c=2×m(H2C2O4)Mr(H2C2O4)×Vc = \frac{2 \times m(\mathrm{H_2C_2O_4})}{M_r(\mathrm{H_2C_2O_4}) \times V}c=2×0.50290×0.0305=0.366 mol/Lc = \frac{2 \times 0.502}{90 \times 0.0305} = 0.366 \ \mathrm{mol/L}


Answer:

0.366 M

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