Question

in the Reversible reaction A+B⇌C+D The concentration of each C and D at equilibrium was 0.8 mole/litre then the equilibrium constant Kc will be.

Answer 1

Answer on Question#48968 – Chemistry – Inorganic Chemistry

in the Reversible reaction $A + B \rightleftharpoons C + D$ The concentration of each C and D at equilibrium was 0.8 mole/litre then the equilibrium constant Kc will be.

Solution:

$$A + B \rightleftharpoons C + D$$ $$K_{C} = \frac{[C]^{C}[D]^{d}}{[A]^{d}[B]^{b}} = \text{const}$$ $$a = v A; \ b = v B; \ c = v C; \ d = v D;$$ $$a A + b B \rightleftharpoons c C + d D; \ a = b = c = d = 1;$$ $$[C] = [D] = 0.8 \ \text{mol/L};$$ $$A + B \rightleftharpoons C + D$$ $$[ ], \ \text{mol/L} \ ? \quad ? \quad 0.8 \quad 0.8$$ $$v \quad 1 \quad 1 \quad 1 \quad 1$$ $$[A] = [B] = [C] = [D] = 0.8 \ \text{mol/L};$$ $$K_{C} = \frac{[C]^{C}[D]^{d}}{[A]^{d}[B]^{b}} = 1$$

Answer: 1

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