Question #48957

Determine the first three energy levels 3 of an electron confined to a one dimensional box of length of 10-9 M.

Expert's answer

Question #48957, Chemistry, Inorganic Chemistry

Question:

Determine the first three energy levels 3 of an electron confined to a one dimensional box of length of 10910^{-9} M.

Answer:


E1=h28mL2=(6.631034Js)28×9.11031kg×(109m)2=6.041017JE _ {1} = \frac {h ^ {2}}{8 m L ^ {2}} = \frac {\left(6.63 \cdot 10 ^ {- 34} J \cdot s\right) ^ {2}}{8 \times 9.1 \cdot 10 ^ {- 31} kg \times \left(10 ^ {- 9} m\right) ^ {2}} = 6.04 \cdot 10 ^ {- 17} JE2=22E1=4×6.041017J=2.421016JE _ {2} = 2 ^ {2} E _ {1} = 4 \times 6.04 \cdot 10 ^ {- 17} J = 2.42 \cdot 10 ^ {- 16} JE3=32E1=9×6.041017J=5.431016JE _ {3} = 3 ^ {2} E _ {1} = 9 \times 6.04 \cdot 10 ^ {- 17} J = 5.43 \cdot 10 ^ {- 16} J


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