Question

Calculate the magnetic moment in 1113 units for a paramagnetic substance having three unpaired electrons.

Answer 1

Answer on Question #48946 – Chemistry – Inorganic Chemistry

Question:

Calculate the magnetic moment in 1113 units for a paramagnetic substance having three unpaired electrons.

Answer:

The effective magnetic moment caused by spin values for paramagnetic compound is defined:

$\mu = g \times [S(S + 1)]^{1/2}$, where $S$ – a total spin for the unit, $g$ – the constant being of 2.0023

The total spin equals:

$S = n \times 1/2 = 3 \times 1/2 = 3/2$, where $n$ – the number of unpaired electrons.

Thus, for 1 unit, $\mu = 2.0023 \times [3/2(3/2 + 1)]^{1/2} = 3.87 \mu_{B}$, where $\mu_{B} = 9.274 \times 10^{-24} \, \text{J T}^{-1}$

The total magnetic moment can be found from the equation:

$M = m \times \mu$, where $m$ – the number of units.

So, $M = 1113 \times 3.87 \mu_{B} = 4307.31 \mu_{B} = 39946 \times 10^{-24} \, \text{J T}^{-1} \approx 4 \times 10^{-20} \, \text{J T}^{-1}$

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