Question

A sample of argon occupies a volume of 200 ml at STP. if the pressure is increased to 1520 torr and the temperature is decreased t 136.5 k, then the final volume is

Answer 1

Answer on Question #48664 - Chemistry – Inorganic Chemistry

Question

A sample of argon occupies a volume of 200 ml at STP. if the pressure is increased to 1520 torr and the temperature is decreased to 136.5 K, then the final volume is.

Answer:

The combined gas law or general gas equation shows the relationship between the pressure, volume, and temperature for a fixed mass of gas:

$$\frac {p _ {1} V _ {1}}{T _ {1}} = \frac {p _ {2} V _ {2}}{T _ {2}}$$

$p_1$ is the standard pressure, $p_1 = 100.00 \mathrm{kPa}$;

$V_{1}$ is the initial volume, $V_{1} = 200 \mathrm{ml} = 0.200 \mathrm{l} = 2 \cdot 10^{-4} \mathrm{~m}^{3}$;

$T_{1}$ is the standard temperature, $T_{1} = 0^{\circ}C = 273.15\mathrm{K}$;

$p_2 = 1520\mathrm{torr} = 202.65\mathrm{kPa};$

$T_{2} = 136.5\mathrm{K}$

Then the final volume of argon is:

$$V _ {2} = \frac {p _ {1} V _ {1} T _ {2}}{p _ {2} T _ {1}} = \frac {1 0 0 . 0 0 \cdot 2 \cdot 1 0 ^ {- 4} \cdot 1 3 6 . 5}{2 0 2 . 6 5 \cdot 2 7 3 . 1 5} = 4. 9 3 \cdot 1 0 ^ {- 5} m ^ {3} = 4. 9 3 \cdot 1 0 ^ {- 2} l = 4 9. 3 m l$$

Answer: The final volume of argon is 49.3 ml.

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