Question

an orange coloured solution(X) acidified with H2SO4 and treated with H2O2, gives a blue solution of CrO5. what is (X)?

Answer 1

Question #48542, Chemistry, Inorganic Chemistry

Question:

An orange colored solution(X) acidified with $\mathrm{H}_2\mathrm{SO}_4$ and treated with $\mathrm{H}_2\mathrm{O}_2$, gives a blue solution of $\mathrm{CrO}_5$. What is (X)?

Answer:

Chromium peroxide is formed as the result of treatment $\mathrm{H}_2\mathrm{Cr}_2\mathrm{O}_7$ (has orange color of $\mathrm{Cr}_2\mathrm{O}_7^{2-}$ ion in aqueous solution) with $\mathrm{H}_2\mathrm{O}_2$ in the acid solution. The balanced equation of the reaction:

$$\mathrm{H}_2\mathrm{Cr}_2\mathrm{O}_7\ (\mathrm{aq}) + 4\mathrm{H}_2\mathrm{O}_2\ (\mathrm{aq}) \rightarrow 2\mathrm{CrO}_5\ (\mathrm{aq}) + 5\mathrm{H}_2\mathrm{O}$$

Therefore, the compound X is $\mathrm{H}_2\mathrm{Cr}_2\mathrm{O}_7$.

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