Question #47592

How many 204Pb atoms are there in an 857 mg lead sample?

Expert's answer

Question #47592, Chemistry, Inorganic Chemistry

Mass fraction of 204Pb^{204}\mathrm{Pb} is 1.4%. So, mass of 204Pb^{204}\mathrm{Pb} is the sample is:


m204Pb=1.4857100=11.998gm_{204Pb} = \frac{1.4 * 857}{100} = 11.998\,gν204Pb=11.998204=0.059mol\nu_{204Pb} = \frac{11.998}{204} = 0.059\,molN204Pb=0.0596.021023=3.551022N_{204Pb} = 0.059 * 6.02 * 10^{23} = 3.55 * 10^{22}


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