Question #46953

Calculate the number of moles (of molecules) in the following samples.(Avogadro's # = 6.02 x 1023 molecules per mole)
(A) 9.93 g H2O

Expert's answer

Question #46953 – Chemistry – Inorganic Chemistry

Question:

Calculate the number of moles (of molecules) in the following samples. (Avogadro's # = 6.02 x 10²³ molecules per mole)

(A) 9.93 g H₂O

Answer:

The mass of one atom of hydrogen is 1.67 × 10⁻²⁴ g, the mass of one atom of oxygen is 26.72 × 10⁻²⁴ g. Hence, the mass of one H₂O molecule is:


m(H2O)=2×(1.67×1024g)+26.72×1024g=30.06×1024g.\mathrm{m(H_2O)} = 2 \times (1.67 \times 10^{-24} \mathrm{g}) + 26.72 \times 10^{-24} \mathrm{g} = 30.06 \times 10^{-24} \mathrm{g}.


One mole contains 6.02 × 10²³ molecules of water, therefore the mass of one mole is:


M(H2O)=30.06×1024g×6.02×1023mol1=18.096g/mole\mathrm{M(H_2O)} = 30.06 \times 10^{-24} \mathrm{g} \times 6.02 \times 10^{23} \mathrm{mol}^{-1} = 18.096 \mathrm{g/mole}


We have 9.93 g, so corresponding the number of moles can be estimated:


N(H2O)=mx(H2O)/M(H2O)=9.93g/18.096g/mole=0.55moles\mathrm{N(H_2O)} = \mathrm{m_x(H_2O)/M(H_2O)} = 9.93 \mathrm{g}/18.096 \mathrm{g/mole} = 0.55 \mathrm{moles}

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