Question

If 3.0 L of oxygen gas at is cooled at constant pressure until the volume becomes 1.50 L, then what is the final temperature?

Answer 1

Question #46808, Chemistry, Inorganic Chemistry

If 3.0 L of oxygen gas at is cooled at constant pressure until the volume becomes 1.50 L, then what is the final temperature?

Answer:

To solve this problem you need to use Charles law equations $V_{1} / T_{1} = V_{2} / T_{2}$.

Because initial conditions are not specified, then we take the standard ambient temperature and pressure (SATP).

$$T_{1} = 25^{\circ}C = 298\ \text{K}$$ $$V_{1} = 3.0\ \text{L}$$ $$V_{2} = 1.5\ \text{L}$$ $$T_{2} = ?$$ $$\begin{array}{l} V_{1} / T_{1} = V_{2} / T_{2} \\ T_{2} = (T1 \cdot V2) / V_{1} \\ \end{array}$$ $$T_{2} = (298 \cdot 1.5) / 3 = 149\ (\text{K})$$