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Question #45030
A saturated solution of BaSO4 at 250C contains 3.9 10 -5 mole/liter of Ba2+ ions. What is the Ksp of this salt?
A) 3.9 10^-5
B) 3.9 10^-6
C) 2.1 10^-7
D) 1.5 10^-8
E) 1.5 10^-9
Expert's answer
Answer on Question #45030, Chemistry, Inorganic Chemistry
K
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p
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B
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⋅
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K_{sp} \left(BaSO_4\right) = \left[Ba^{2+} \right] \cdot \left[SO_4^{2-}\right]
K
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[
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\left[Ba^{2+} \right] = \left[SO_4^{2-}\right]
[
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+
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=
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S
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K
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3.9
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1.5
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9
K_{sp} \left(BaSO_4\right) = \left[Ba^{2+} \right]^2 = (3.9 \cdot 10^{-5})^2 = 1.5 \cdot 10^{-9}
K
s
p
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B
a
S
O
4
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=
[
B
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2
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3.9
⋅
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5
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2
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1.5
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1
0
−
9
Answer E
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