Question

The specific heat of tungsten is 0.03 cal/g˚C. If a 50 gram sample of tungsten absorbs 100 calories of heat, what will be the change in temperature of the sample?

Answer 1

Answer on Question #45018 – Chemistry – Inorganic Chemistry

Question

The specific heat of tungsten is 0.03 cal/g·°C. If a 50 gram sample of tungsten absorbs 100 calories of heat, what will be the change in temperature of the sample?

Solution

The heat absorbed by the sample (Q) equals to:

$$Q = m \cdot C \cdot \Delta T,$$

where m – mass of the sample, g; C – specific heat of the sample material, cal/g·°C; ΔT – change in temperature of the sample.

Hence

$$\Delta T = Q / m \cdot C = 100 \text{ cal} / 50 \text{ g} \cdot 0.03 \text{ cal/g} \cdot ^\circ \text{C} = 66.7^\circ \text{C}$$

Answer: 66.7 °C

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