Question #44486

On addition of conc.sulphuricacid to chloride salt, colourless fumes are evolved but in case of iodine salt,violet fumes come out.this is because

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Answer on Question #44486 – Chemistry – Inorganic Chemistry

Question

On addition of concentrated sulphuric acid to chloride salt, colourless fumes are evolved but in case of iodine salt, violet fumes come out. This is because...

Answer

Concentrated sulphuric acid is a strong oxidant, and chlorine and iodine in oxidation state -1 entering into the composition of corresponding salts are reducers.

In case of chloride salt the red-ox reaction is as follows


1+60+4\begin{array}{c c c c} - 1 & + 6 & 0 & + 4 \end{array}2NaCl+2H2SO4Cl2+SO2+Na2SO4+2H2O2 \mathrm{NaCl} + 2 \mathrm{H_2SO_4} \longrightarrow \mathrm{Cl_2\uparrow} + \mathrm{SO_2\uparrow} + \mathrm{Na_2SO_4} + 2 \mathrm{H_2O}


Two gasses, namely Cl2\mathrm{Cl_2} and SO4\mathrm{SO_4} are evolved as a result of the red-ox reaction. SO4\mathrm{SO_4} is colourless and Cl2\mathrm{Cl_2} is pale green. That is why the fumes evolved looks colourless.

In case of iodine salt the red-ox reaction is as follows


1+60+4\begin{array}{c c c c} - 1 & + 6 & 0 & + 4 \end{array}2NaI+2H2SO4I2+SO2+Na2SO4+2H2O2 \mathrm{NaI} + 2 \mathrm{H_2SO_4} \longrightarrow \mathrm{I_2\uparrow} + \mathrm{SO_2\uparrow} + \mathrm{Na_2SO_4} + 2 \mathrm{H_2O}


Under ambient conditions I2\mathrm{I_2} is a solid, but at the elevated temperature it is a violet gas. In given reaction I2\mathrm{I_2} is evolved as a violet gas. That is why the violet fumes come out.

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