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Answer to Question #4432 in Inorganic Chemistry for Victor
Question #4432
break the following equations into two half equation.One for oxidation and one for reduction. 2cl(g)+2I(aq)=2cl(aq)+I2(aq)
Expert's answer
Correctly, this equation can be written as:
Сl2(g)+2I-(aq)=2Сl-(aq)+I2(aq)
Oxidation: Сl2(g)→2Сl-(aq) +2e-
Reduction: 2I-(aq) +2e- →I2(aq)
Сl2(g)+2I-(aq)=2Сl-(aq)+I2(aq)
Oxidation: Сl2(g)→2Сl-(aq) +2e-
Reduction: 2I-(aq) +2e- →I2(aq)
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