Question

For the cell reaction represented as
Co/Co2+//Ni2+/Ni
Calculate the cell potential and free energy of reaction.

Answer 1

Answer on Question #44008 - Chemistry - Inorganic Chemistry

Question:

For the cell reaction represented as

$$\mathrm{Co}/\mathrm{Co}^{2+}//\mathrm{Ni}^{2+}/\mathrm{Ni}$$

Calculate the cell potential and free energy of reaction.

Answer:

Standard electrode potential $\mathrm{Co}/\mathrm{Co}^{2+} \mathrm{E}^{\circ}_{\mathrm{L}} = -0.27 \mathrm{~V}$ and $\mathrm{Ni}^{2+}/\mathrm{Ni} \mathrm{E}^{\circ}_{\mathrm{R}} = -0.24$

Cell potential:

$$E^{\circ} = E^{\circ}_{R} - E^{\circ}_{L}$$ $$E^{\circ} = -0.24 - (-0.27) = 0.03 \mathrm{~V}$$

Free energy or Gibbs energy:

$$\Delta G = -n \cdot F \cdot E^{\circ},$$

$n$ is the number of electrons participating in the reaction; $F$ - Faraday number 96485 C·mol⁻¹

$$\Delta G = -2 \cdot 96485 \cdot 0.03 = -5789.1 \mathrm{~J}/\mathrm{mol}$$

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