Question #43737

if the density of methanol is 0.793 kg/L ,what is its volume needed for making 2.5L of its 0.25M solution?

Expert's answer

Answer on Question #43737, Chemistry, Inorganic Chemistry

Question:

if the density of methanol is 0.793 kg/L, what is its volume needed for making 2.5L of its 0.25M solution?

Solution:

2.5L of 0.25M solution contains 2.5×0.25=0.6252.5 \times 0.25 = 0.625 mole of methanol.

Its mass is equal to 0.625mol×32g/mol=20g0.625 \, \text{mol} \times 32 \, \text{g/mol} = 20 \, \text{g}

0.793kg/L=0.793g/ml0.793 \, \text{kg/L} = 0.793 \, \text{g/ml}

Now we can find needed volume:

V(CH3OH)=(20g)/(0.793g/ml)=25.22mlV(\mathrm{CH}_3\mathrm{OH}) = (20 \, \text{g}) / (0.793 \, \text{g/ml}) = 25.22 \, \text{ml}

Answer: 25.22 ml

http://www.AssignmentExpert.com/


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS