Question #43192

25.3g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250ml of solution. If sodium carbonate dissociates completely , molar concentration of sodium ion , Na+ and carbonate ions are respectively?
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Expert's answer

2014-06-09T07:44:51-0400

Answer on Question #43192, Chemistry, Inorganic Chemistry

Question:

25.3g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250ml of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions are respectively?

Solution:

Na2CO32Na++CO3\mathrm{Na_2CO_3} \rightarrow 2\mathrm{Na^+} + \mathrm{CO_3^-}n(Na2CO3)=n(CO3)=m/M=25.3/106=0.24 molen(Na+)=2n(Na2CO3)=2×0.24=0.48 moleC(CO3)=n/V=0.24 mole/0.25 L=0.96 mole/LC(Na+)=n/V=0.48 mole/0.25 L=1.92 mole/L\begin{aligned} n(\mathrm{Na_2CO_3}) &= n(\mathrm{CO_3^-}) = \mathrm{m/M} = 25.3 / 106 = 0.24 \text{ mole} \\ n(\mathrm{Na^+}) &= 2n(\mathrm{Na_2CO_3}) = 2 \times 0.24 = 0.48 \text{ mole} \\ C(\mathrm{CO_3^-}) &= n/V = 0.24 \text{ mole} / 0.25 \text{ L} = 0.96 \text{ mole/L} \\ C(\mathrm{Na^+}) &= n/V = 0.48 \text{ mole} / 0.25 \text{ L} = 1.92 \text{ mole/L} \end{aligned}

Answer:

1.92 mole/L and 0.96 mole/L of sodium ions and carbonate ions respectively.

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