Question

Total number of valence electrons in 4.2g of Nitride ion ?

Answer 1

Answer on Question #42554 - Chemistry - Inorganic Chemistry

Question

Total number of valence electrons in 4.2 g of Nitride ion?

Solution

The nitride ion is a nitrogen ion of charge 3-: $\mathsf{N}^{3-}$

Its Lewis dot structure is:

As is clear from the Lewis structure the number of valence electrons in a single nitride ion is equal to 8.

Number of nitride ions in 4.2 g is

$$N_{N^{3-}} = \frac{m_{N^{3-}}}{M_{N^{3-}}} N_{A} = \frac{4.2\ g}{14.0\ g/mol} \cdot 6.02 \cdot 10^{23} \cdot mol^{-1} = 1.8 \cdot 10^{23},$$

where $M_{N^{3-}}$ – molar weight of nitride ion, $N_{A}$ – Avogadro’s number.

Thus, the total number of valence electrons in 4.2 g of nitride ion is

$$N_{e} = 8 \cdot N_{N^{3-}} = 8 \cdot 1.8 \cdot 10^{23} = 1.4 \cdot 10^{24}$$

Answer: 1.4·10²⁴ electrons

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