Question

N2+3H2--->2NH3

If 0.3 mole of N2 were reacted with 0.6 mole of H2, what mass of NH3 could form?
AW's: N=14g, H=1g

Answer 1

Answer on the Question #42452, Chemistry, Inorganic Chemistry

Question:

$$N_2 + 3H_2 \longrightarrow 2NH_3$$

If 0.3 mole of $N_2$ were reacted with 0.6 mole of $H_2$, what mass of $NH_3$ could form?

AW's: $N=14g$, $H=1g$

Solution:

```

0.6 mol x g

N₂ + 3H₂ ---> 2NH₃

3 mol 34g

```

$x = 6.8g$

The calculations are based on the amount of $H_2$ because the $N_2$ is in excess.

Answer:

6.8g

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