Question

a sample of argon has a pressure of 175kPa when its temperature is 77c. if its temperature is increased to 154c and the volume is held constant, what is the new pressure?

Answer 1

Answer on Question #42380 - Chemistry - Inorganic Chemistry

Question:

A sample of argon has a pressure of 175 kPa when its temperature is 77 °C. If its temperature is increased to 154 °C and the volume is held constant, what is the new pressure?

Solution:

It is given that

$p_1 = 175 \mathrm{kPa},$

$V_{1} = V_{2},$

$T_{1} = 77^{\circ}\mathrm{C} = 350\mathrm{K}$

$T_{2} = 154^{\circ}\mathrm{C} = 427\mathrm{K}$

$p_2 = ?$

According to the combined gas law or general gas equation

$$\frac {p _ {1} V _ {1}}{T _ {1}} = \frac {p _ {2} V _ {2}}{T _ {2}}$$

Hence, substituting the given values

$$p _ {2} = \frac {p _ {1} V _ {1} T _ {2}}{T _ {1} V _ {2}} = \frac {p _ {1} T _ {2}}{T _ {1}} = \frac {1 7 5 \cdot 4 2 7}{3 5 0} = 2 1 3. 5 k P a$$

Answer: 213.5 kPa

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