Question #42323

What quantity of 0.25 M HNO3 can be neutralized by 0.10 liters of 0.50 M NaOH?

Expert's answer

Answer on Question #42323 - Chemistry - Inorganic Chemistry

Question:

What quantity of 0.25 M HNO₃ can be neutralized by 0.10 liters of 0.50 M NaOH?

Solution:

The equation is:


HNO3+NaOH=NaNO3+H2O\mathrm{HNO_3} + \mathrm{NaOH} = \mathrm{NaNO_3} + \mathrm{H_2O}


0.1 liter of 0.50 M NaOH solution contains 0.10.5=0.050.1 * 0.5 = 0.05 moles of NaOH

The quantity of HNO3\mathrm{HNO_3} needed to neutralize NaOH is the same to the quantity of NaOH, 0.05 moles.

The quantity of HNO3\mathrm{HNO_3} solution needed is 0.050.25=0.2\frac{0.05}{0.25} = 0.2 l

Answer: 0.2 liters

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