Question

Lithium nitride reacts with water to produce ammonia and lithium hydroxide according to the equation

Li3N(s) +3H2O(l) ---> NH3(g) +3LiOH(aq)

Heavy water is water with the isotope deuterium in place of ordinary hydrogen, and its formula is D2O. The above reaction can be used to produce heavy ammonia, ND3(g), according to the equation,

Li3N(s) +3D2O(l) ---> ND3(g) + 3LiOD(aq)


Calculate how many grams of heavy water are required to produce 175.0 mg of ND3(g). The mass of deuterium, D, is 2.014 g/mol.

Answer 1

Answer on Question #40481 – Chemistry – Other

Lithium nitride reacts with water to produce ammonia and lithium hydroxide according to the equation

$$\mathrm{Li3N(s)} + 3\mathrm{H_2O(l)} \rightarrow \mathrm{NH_3(g)} + 3\mathrm{LiOH(aq)}$$

Heavy water is water with the isotope deuterium in place of ordinary hydrogen, and its formula is D2O. The above reaction can be used to produce heavy ammonia, ND3(g), according to the equation,

$$\mathrm{Li3N(s)} + 3\mathrm{D_2O(l)} \rightarrow \mathrm{ND_3(g)} + 3\mathrm{LiOD(aq)}$$

Calculate how many grams of heavy water are required to produce 175.0 mg of ND3(g). The mass of deuterium, D, is 2.014 g/mol.

Solution

x g 0.175 g

Li3N(s) + 3D2O(l) → ND3(g) + 3LiOD(aq)

60 g 20 g

x = 0.175g · 60g / 20g = 0.525 g

Answer: 0.525 g