Question

CO(g)+H2O-->CO2(g)+H2(g)
In an experiment, .40 mol of CO and .45 mol of H2O were placed in a 1.00 L vessel. At equilibrium there were .18 mol of CO remaining. Keq is what?

Answer 1

Answer on Question#39165, Chemistry, Inorganic Chemistry

Question:

$$\mathrm{CO}(g) + \mathrm{H_2O} \rightarrow \mathrm{CO_2}(g) + \mathrm{H_2}(g)$$

In an experiment, .40 mol of CO and .45 mol of H₂O were placed in a 1.00 L vessel. At equilibrium there were .18 mol of CO remaining. Keq is what?

Solution:

$$K_{eq} = \frac{[CO_2][H_2]}{[CO][H_2O]}$$ $$[CO] = 0.18;$$ $$[H_2O] = 0.45 - (0.40 - 0.18) = 0.23;$$ $$[CO_2] = 0.40 - 0.18 = 0.22;$$ $$[H_2] = 0.40 - 0.18 = 0.22.$$ $$K_{eq} = \frac{0.22 \cdot 0.22}{(0.18 \cdot 0.23)} = 1.17.$$

Answer: 1.17