Question

Calcium carbonate will react with phosphoric acid to produce calcium phosphate,water,and carbondioxide. Determine the amount of water in grams produced by 187.6grams of calcium carbonate react with phosphoric acid.

Answer 1

Answer on Question#39143 - Chemistry - Inorganic Chemistry

Question

Calcium carbonate will react with phosphoric acid to produce calcium phosphate, water, and carbon dioxide. Determine the amount of water in grams produced by 187.6 grams of calcium carbonate react with phosphoric acid.

Answer:

Reaction between calcium carbonate and phosphoric acid:

$$3 \mathrm{CaCO_3}(s) + 2 \mathrm{H_3PO_4}(aq) = \mathrm{Ca_3(PO_4)_2}(aq) + 3 \mathrm{CO_2}(g) + 3 \mathrm{H_2O}(l)$$

Molar mass of $\mathrm{CaCO_3}$ equals:

$$M(\mathrm{CaCO_3}) = M(\mathrm{Ca}) + M(\mathrm{C}) + 3M(\mathrm{O}) = 40 + 12 + 3 \cdot 16 = 40 + 12 + 48 = 100 \frac{g}{\text{mole}}$$

Mass of 3 moles of calcium carbonate equals:

$$3 \cdot 100 = 300g$$

Molar mass of $\mathrm{H_2O}$ equals:

$$M(\mathrm{H_2O}) = 2M(\mathrm{H}) + M(\mathrm{O}) = 2 \cdot 1 + 16 = 18 \frac{g}{\text{mole}}$$

Mass of 3 moles of water equals:

$$3 \cdot 18 = 54g$$

Then we make a proportion:

$$300g \text{ of } \mathrm{CaCO_3} \text{ produce } 54g \text{ of } \mathrm{H_2O}$$ $$187.6g \text{ of } \mathrm{CaCO_3} - xg \text{ of } \mathrm{H_2O}$$ $$x = \frac{187.6 \cdot 54}{300} = 33.768g$$

Answer: $m(\mathrm{H_2O}) = 33.768g$