Question

You have 5.4 moles of NH3 after the reaction . What is the minimum number of moles of H2 before the reaction?

Answer 1

Answer on Question#38414-Chemistry-Inorganic Chemistry

Question

You have 5.4 moles of $\mathrm{NH}_3$ after the reaction. What is the minimum number of moles of $\mathrm{H}_2$ before the reaction?

Solution

The reaction between hydrogen and nitrogen resulting in ammonia formation is

$$3\mathrm{H}_2 + \mathrm{N}_2 \rightarrow 2\mathrm{NH}_3$$

As is clear from the chemical equation, for 2 moles of $\mathrm{NH}_3$ to be formed, 3 moles of $\mathrm{H}_2$ are needed. Thus, we have the proportion:

- 2 moles $\mathrm{NH}_3$ – 3 moles $\mathrm{H}_2$

- 5.4 moles $\mathrm{NH}_3$ – ? moles $\mathrm{H}_2$

- Hence, $n(\mathrm{H}_2) = (5.4 \cdot 3)/2 = 8.1$ moles

Answer: 8.1 moles