Question

starting with solid silver nitrate,describe how you would prepere exactly 100 cm^3 of silver nitrate solution of concentration 0,01 mol dm^3

Answer 1

Answer on Question#37568 - Chemistry - Inorganic Chemistry

$$\mathrm{C} \left( \mathrm{AgNO_3} \right) = 0.01 \, \mathrm{mol} \cdot \mathrm{dm}^{-3}$$ $$\mathrm{V} \left( \mathrm{sol} \cdot \mathrm{AgNO_3} \right) = 100 \, \mathrm{cm}^3 = 0.1 \, \mathrm{dm}^3$$ $$\mathrm{M} \left( \mathrm{AgNO_3} \right) = 169.87 \, \mathrm{g} \cdot \mathrm{mol}^{-1}$$

Determine the mass of silver nitrate:

$$\mathrm{m} \left( \mathrm{AgNO_3} \right) = M \cdot n = M \cdot (C \cdot V) = 169.87 \cdot 0.01 \cdot 0.1 = 0.16987 \, \mathrm{g}$$

The calculated mass of salt placed in a beaker, and then added water. Bring the volume up to 100 ml then stir thoroughly until complete dissolution of silver nitrate. For better dissolution water temperature should not be less than 20 degrees Celsius.

Answer: 0.16987 g $\left( \mathrm{AgNO_3} \right)$ dissolved in 100 ml $\left( H_2O \right)$