Question

calculate the volume in liters occupied by 7.40 g of NH3 at STP

Answer 1

calculate the volume in liters occupied by 7.40 g of NH3 at STP

Solution

At STP 1 mol of any gas occupy 22.4 l

$$n = \frac {m}{M}$$

Where,

n – amount of NH₃

m – mass of NH₃

M – molar mass of NH₃

$$n = \frac {7.4\, g}{17\, \frac {g}{mol}} = 0.435\, mol$$ $$V = V_m \cdot n$$

Where

V – volume of NH₃

Vₘ – molar volume (22.4 l/mol)

n – amount of NH₃

$$V = 22.4\, \text{l/mol} \cdot 0.435\, \text{mol} = 9.744\, \text{l}$$

Answer: 9.744 l