Question

the atmospheric pressure in san francisco on a certain day was 732 mmHg. what was the pressure in kPa?

Answer 1

The atmospheric pressure in San Francisco on a certain day was 732 mmHg. what was the pressure in kPa?

Solution:

760.0 mmHg equals - 101.325 kPa, so

732.0 mmHg equals - X kPa;

That's why $\mathbf{X} = 732.0^{*}101.325 / 760.0 = 97.592\approx 97.6\mathrm{kPa}$

Answer: The pressure San Francisco on a certain day in kPa was - 97.6 kPa