Question

2H2(g)+O2(g)=2H2O(g) Delta H=-483.6kj
3O2(g)=2O3(g) Delta H=+284.6 kj
Calculate the heat of the reaction :
3H2(g)+O3(g)=3h2O(g)

Answer 1

2H2(g)+O2(g)=2H2O(g) Delta H=-483.6kj

3O2(g)=2O3(g) Delta H=+284.6 kJ

Calculate the heat of the reaction :

3H2(g)+O3(g)=3h2O(g)

Solution:

$$2 H _ {2} + O _ {2} = 2 H _ {2} O \tag {a}$$ $$3 O _ {2} = 2 O _ {3} \tag {b}$$ $$3 H _ {2} + O _ {3} = 3 H _ {2} O \tag {c}$$ $$c = \frac {3 a - b}{2}$$

Delta H (c) (kJ) = (3 * (-483.6) - 284.6) / 2 = -867.7

Answer: -867.7 kJ